-x^2+360x-100=0

Solution for -x^2+360x-100=0 equation:

-x^2+360x-100=0

We add all the numbers together, and all the variables

-1x^2+360x-100=0

a = -1; b = 360; c = -100;
Δ = b2-4ac
Δ = 3602-4·(-1)·(-100)
Δ = 129200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{129200}=\sqrt{400*323}=\sqrt{400}*\sqrt{323}=20\sqrt{323}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(360)-20\sqrt{323}}{2*-1}=\frac{-360-20\sqrt{323}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(360)+20\sqrt{323}}{2*-1}=\frac{-360+20\sqrt{323}}{-2}
$